Let’s observe the addition sums given below.
2 + 22 + 222 + 2222 = ?
4 + 44 + 444 + 4444 + 4444 = ?
5 + 55 + 555 + 5555 + 55555 + 555555 + 5555555 + 55555555 = ?
7 + 77 + 777 + 7777 + 77777 + 777777 = ?
8 + 88 + 888 + 8888 + 88888 + 888888 + 8888888 = ?
9 + 99 + 999 + 9999 + 99999 + 999999 + 9999999 = ?
In case, If you find addition sums with the numbers having same digit repeated in increasing order, follow the steps recommended below. This technique helps you finding answer in just few seconds. Let’s take some examples to understand the concept.
Example 1:- 2 + 22 + 222 + 2222 = ?
Step 1:- Count the number of digits in each number. Here, its 1 2 3 4.
Step 2:- Consider the number of digits as a number. Here, 1234 becomes a new number to to considered.
Step 3:- Multiply the number obtained in previous step by 2 (the digit which repeats). Here, 1234 × 2 = 2468
Ans. 2468
Example 2:- 7 + 77 + 777 + 7777 + 77777 + 777777 = ?
Step 1:- Count the number of digits in each number. Here, its 1 2 3 4 5 6.
Step 2:- Consider the number of digits as a number. Here, 123456 becomes a new number to be considered.
Step 3:- Multiply the number obtained in previous step by 7 (the digit which repeats). Here, 123456 × 7 = 864192
Ans. 864192
Wow! That’s so easy……………………
HAPPY LEARNING…………………